(2x^4y^8)^3/(4x^8y^4)^2

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Solution for (2x^4y^8)^3/(4x^8y^4)^2 equation: 


D( x )

(4*x^8*y^4)^2 = 0

(4*x^8*y^4)^2 = 0

(4*x^8*y^4)^2 = 0

16*x^16*y^8 = 0 // : 16*y^8

x^16 = 0

x = 0

x in (-oo:0) U (0:+oo)

((2*x^4*y^8)^3)/((4*x^8*y^4)^2) = 0

1/2*x^-4*y^16 = 0 // : 1/2*y^16

x^-4 = 0

x naleu017Cy do O

x belongs to the empty set

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